Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 259: 8

Answer

$XZ = 12$ $YZ= 12$

Work Step by Step

By the given Figure $\angle Z=90^{\circ}$ given $\angle X=45^{\circ}$ given So remaining$ \angle Y=45^{\circ}$ now $XY= 12 \sqrt 2$ given By Theorem 5.5.1/ (45-45-90 Theorem) $XZ = 12$ $YZ= 12$
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