Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 259: 16

Answer

PM=10 NP=10

Work Step by Step

PM=NP=$\frac{MN}{\sqrt 2}$ PM=NP=$\frac{10\sqrt 2}{\sqrt 2}$ PM=NP=10
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