Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 259: 5

Answer

YZ = 8 XY= 8$\sqrt 2$

Work Step by Step

By the given Figure $\angle Z=90^{\circ}$ given $\angle X = 45^{\circ}$ given So remaining $\angle Y = 45^{\circ}$ now XZ = 8 given YZ = 8 XY= 8$\sqrt 2$ By Theorem 5.5.1/ (45-45-90 Theorem)
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