#### Answer

$DE = 12$
$FE= 24$

#### Work Step by Step

By the given Figure
$\angle E= 60^{\circ}$
So remaining $\angle F= 30^{\circ}$
$FD= 12 \sqrt 3$ given
Now by Theorem 5.5.2 / (30-60-90 Theorem)
$DE = 12$
$FE= 24$

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$DE = 12$
$FE= 24$

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