Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 259: 14

Answer

$RS= 3\sqrt 2 \approx 4.24$ $ST= 3\sqrt 2\times\sqrt 3 \approx 7.34$

Work Step by Step

In △RST $\angle STV=150^{\circ}$ So $\angle STR=180-150=30^{\circ}$ because supplementary angles So $\angle SRT= 60^{\circ}$ now By Theorem 5.5.2/ (30-60-90 Theorem) $RT=6\sqrt 2$ given $RS= 3\sqrt 2 \approx 4.24$ $ST= 3\sqrt 2\times\sqrt 3 \approx 7.34$
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