Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Review Exercises - Page 386: 36


$A_{ring} = \pi BC^2$

Work Step by Step

We call r the radius of the smaller circle. The radius of the larger circle is: $ R = \sqrt{BC^2 + r^2}$ Thus, the area of the ring is: $A = \pi (R^2 - r^2) \\ A = \pi (BC^2 + r^2 - r^2) = \pi BC^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.