Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Review Exercises - Page 386: 34b



Work Step by Step

We first find the radius: $A = \pi r^2 \\ 27 \pi = \pi r^2 \\ r = \sqrt{27} = 3\sqrt{3}$ We know that the perimeter contains double the radius plus 80/360 of the circumference of the circle: $ P = 2\pi(3\sqrt{3})(80/360) + 6\sqrt3 = 17.65 $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.