## Elementary Geometry for College Students (6th Edition)

$17.65$
We first find the radius: $A = \pi r^2 \\ 27 \pi = \pi r^2 \\ r = \sqrt{27} = 3\sqrt{3}$ We know that the perimeter contains double the radius plus 80/360 of the circumference of the circle: $P = 2\pi(3\sqrt{3})(80/360) + 6\sqrt3 = 17.65$