#### Answer

$17.65$

#### Work Step by Step

We first find the radius:
$A = \pi r^2 \\ 27 \pi = \pi r^2 \\ r = \sqrt{27} = 3\sqrt{3}$
We know that the perimeter contains double the radius plus 80/360 of the circumference of the circle:
$ P = 2\pi(3\sqrt{3})(80/360) + 6\sqrt3 = 17.65 $