Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Review Exercises - Page 386: 31


A=25$\sqrt 3$-$\frac{25}{3}$

Work Step by Step

height of triangle=.5s$\sqrt 3$ h=5$\sqrt 3$ radius of circle= apothem=$\frac{1}{3}$h r=$\frac{5\sqrt 3}{3}$ A=.5(10)(5$\sqrt 3$)-$\pi$($\frac{5\sqrt 3}{3}$)$^2$ A=25$\sqrt 3$-$\frac{25}{3}$
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