Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 8 - Review Exercises - Page 386: 32

Answer

A=5$\pi$ l=$\frac{2\pi\sqrt 5}{3}$

Work Step by Step

Total circumference=2$\pi$r=6$\pi$$\sqrt 5$ Total area=$\pi$r$^2$=45$\pi$ Area of sector=$\frac{1}{9}$(45$\pi$)=5$\pi$ Length of arc=$\frac{1}{9}$(6$\pi$$\sqrt 5$)=$\frac{2\pi\sqrt 5}{3}$
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