Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Review Exercises - Page 386: 34a


A=6$\pi$ ft$^2$

Work Step by Step

$\frac{80}{360}$=$\frac{2}{9}$ A=$\frac{2}{9}$(27$\pi$) A=6$\pi$ ft$^2$
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