Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 10 - Section 10.5 - Equations of Lines - Exercises - Page 471: 24


$10x - 8y = -39$

Work Step by Step

We find the slope of the original line: $m=\frac{5-1}{-4-1} = \frac{-4}{5}$ The slope of the perpendicular line is the opposite reciprocal, which is 5/4. The line's midpoint is $(-1.5,3)$, which is the average of the x and y endpoints. We obtain the equation, first using point slope form: $y-3 = 5/4(x+1.5) \\ 4y-12=5(x+1.5) \\ 4y-12 = 5x + 7.5 \\ -5x+4y=19.5 \\ 10x - 8y = -39$
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