## Elementary Geometry for College Students (6th Edition)

$x-y=2$
If the line has intercepts $a=2$ and $b=-2$ this means it contains $(2,0)$ and $(0,-2)$ . We need to find the slope now: $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}= \frac{-2-0}{0-2}=\frac{-2}{-2}=1$ Now, with the slope-intercept form, with m=1 and passing through $(2,0)$, the equation is: $y-y_{1}=m\times (x-x_{1})= y-0 = 1\times (x-2)$ So $x-y=2$