Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 10 - Section 10.5 - Equations of Lines - Exercises - Page 471: 18



Work Step by Step

If the line has intercepts $a=-3$ and $b=5$ this means it contains $(-3,0)$ and $(0,5)$ . We need to find the slope now: $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}= \frac{5-0}{0-(-3)}=\frac{5}{3}$ Now, with the slope-intercept form, with m=$\frac{5}{3}$ and passing through $(-3,0)$, the equation is: $y-y_{1}=m\times (x-x_{1})= y-0 = \frac{5}{3}\times (x-(-3))$ $y=\frac{5}{3}\times x +5$ So $\frac{5}{3}x-y=-5$
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