Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 10 - Section 10.5 - Equations of Lines - Exercises - Page 471: 14


x-2y = -2

Work Step by Step

The line contains(-2,0) and (4,3) To find the equation of the line. To use the point slope form, we need to find the slope of the line using (-2,0) and (4,3) m = $\frac{y2-y1}{x2-x1}$ = $\frac{3-0}{4-(-2)}$ =$\frac{3}{6}$ = $\frac{1}{2}$ then, y-y1 = m(x-x1) y-0 =$\frac{1}{2}$ (x-(-2)) y= $\frac{1}{2}$ (x+2) 2y=x+2 x-2y = -2
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