## Elementary Geometry for College Students (6th Edition)

$3x+2y=0$
When two lines are perpendicular in standard form, the coefficient in front of the x term is switched with the coefficient in front of the y term. Then, the new coefficient in front of the y term is made negative. After doing this, we plug in the point to find the new constant: $-3x-2y = c \\ -3(-2)-2(3) = c \\ c= 0$ Thus, we find: $-3x-2y=0 \\ 3x+2y=0$