Answer
$\sqrt{26.42}$
Work Step by Step
I know that for the vector $v=\begin{bmatrix}
v_{1} \\
v_{2} \\
\vdots\\
v_{n}
\end{bmatrix}$
$||v||=\sqrt{v_1^2+v_2^2+...+v_n^2}$
The distance of two vectors $u$ and $v$ is: $d=||u-v||$.
Hence: $d=||\begin{bmatrix}
3.2 \\
-0.6 \\
-1.4 \\
\end{bmatrix}-\begin{bmatrix}
1.5 \\
4.1 \\
-0.2\\
\end{bmatrix}||=||\begin{bmatrix}
1.7 \\
-4.7 \\
-1.2\\
\end{bmatrix}||=\sqrt{1.7^2+(-4.7)^2+(-1.2)^2}=\sqrt{2.89+22.09+1.44}=\sqrt{26.42}$
