Answer
$$\pi \sqrt 3$$
Work Step by Step
We need to integrate the integral to compute the volume.
We have:
$$Volume = \int_{0}^{1} (y^2) dy \times \pi \\= \pi [\dfrac{y^3}{3}]_{0}^{\sqrt 3} \\= \pi (\dfrac{3 \sqrt 3}{3}) \\=\pi \sqrt 3$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 6 - Section 6.1 - Volumes Using Cross-Sections - Exercises - Page 356: 48
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
