University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.1 - Volumes Using Cross-Sections - Exercises - Page 356: 22

Answer

$$\dfrac{\pi}{30}$$

Work Step by Step

We need to integrate the integral to compute the volume. $$Volume= \int_{0}^{1} \pi (x^2-2x^3+x^4) \space dx \\ =[\dfrac{x^3}{3}-\dfrac{2x^4}{4}+\dfrac{x^5}{5}]_0^1 \\=\dfrac{(\pi)}{3}-\dfrac{(\pi)}{2}+\dfrac{(\pi)}{5} \\=\dfrac{\pi}{30}$$
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