Answer
$$4 \pi \ln 4$$
Work Step by Step
We need to integrate the integral to compute the volume.
We have:
$$Area =\pi r^2=\pi (\dfrac{2}{\sqrt {y+1}})^2=\dfrac{4 \space \pi}{y+1}$$
Now,
$$Volume= (4 \pi) \times \int_{0}^{3} \dfrac{1}{y+1} \space dy \\= 4 \pi [\ln |y+1|]_{0}^{3} \\=4 \pi (\ln 4 -0) \\=4 \pi \ln 4$$
