Answer
$$36 \pi$$
Work Step by Step
We need to integrate the integral to compute the volume.
$Volume= (2) \times \int_{0}^{3} \pi (9-x^2) \space dx \\=( 2\pi)\times [9x-\dfrac{x^3}{3}]_0^3 \\=(2 \pi)(27-9) \\=36 \pi$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 6 - Section 6.1 - Volumes Using Cross-Sections - Exercises - Page 356: 21
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