Answer
$$\int\cot xdx=\ln|\sin x|+C$$
Work Step by Step
$$A=\int\cot xdx=\int\frac{\cos x}{\sin x}dx$$
Set $u=\sin x$, then $$du=\cos xdx$$
Therefore,
$$A=\int\frac{du}{u}=\ln|u|+C$$ $$A=\ln|\sin x|+C$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.5 - Indefinite Integrals and the Substitution Method - Exercises - Page 330: 71
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