Answer
$$\int (\cos x)e^{\sin x}dx=e^{\sin x}+C$$
Work Step by Step
$$A=\int (\cos x)e^{\sin x}dx$$
We set $u=\sin x$
Then $$du=\cos xdx$$
Therefore, $$A=\int e^udu= e^u+C$$ $$A=e^{\sin x}+C$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.5 - Indefinite Integrals and the Substitution Method - Exercises - Page 330: 51
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