Answer
$\$4500$
Work Step by Step
Here, we have $\int_0^{3}2- \dfrac{2}{(x+1)^2} dx$
or, $\int_0^{3}2- \dfrac{2}{(x+1)^2} dx=[2x+\dfrac{2}{x+1}]_0^3$
Thus, $6+\dfrac{2}{4}-0-2=4.5$
Hence, $\$4500$
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