Answer
$4$
Work Step by Step
We can calculate the area, by integrating the function from -2 to 2.
$\int_{-2}^{2} (3x^2-3)dx =[x^3-3x]_{-2}^{2}=[2^3-3\cdot2]-[(-2)^3-3\cdot(-2)]=[8-6]-[-8+6]=2-(-2)=4$
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