Answer
$y=\int_{2}^{x} \sec t dt+3$
Work Step by Step
We are given that $\dfrac{dy}{dx}=\sec x$
$\dfrac{d}{dx}\int_{2}^{x} \sec t dt+3=\sec x$
This implies that
$y(2)=\int_{-2}^{2} \sec t dt+3 =0+3=3$
Hence, $y=\int_{2}^{x} \sec t dt+3$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 321: 69
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
