University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 321: 65


$d$ is a solution to the given problem.

Work Step by Step

We are given that $\dfrac{dy}{dx}=\dfrac{1}{x}$ $\dfrac{d}{dx}[\int_0^{x} \dfrac{1}{t} dt -3]=\dfrac{1}{x}$ This implies that $y(\pi)=\int_{\pi}^{\pi} \dfrac{1}{t} dt -3=0-3=-3$ Thus, $d$ is a solution to the given problem.
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