## University Calculus: Early Transcendentals (3rd Edition)

$d$ is a solution to the given problem.
We are given that $\dfrac{dy}{dx}=\dfrac{1}{x}$ $\dfrac{d}{dx}[\int_0^{x} \dfrac{1}{t} dt -3]=\dfrac{1}{x}$ This implies that $y(\pi)=\int_{\pi}^{\pi} \dfrac{1}{t} dt -3=0-3=-3$ Thus, $d$ is a solution to the given problem.