University Calculus: Early Transcendentals (3rd Edition)

$3\cdot(\int_{0}^{x} ({t^3+1})^{10}dt)^2 (x^3+1)^{10}$
Let's differentiate both sides and then use the chain rule to differentiate! $\frac{dy}{dx}=\frac{d}{dx}(\int_{0}^{x} ({t^3+1})^{10}dt)^3=3\cdot(\int_{0}^{x} ({t^3+1})^{10}dt)^2 (x^3+1)^{10}$