Answer
$y=3x^3-2x^2+5x+10$
Work Step by Step
We need to find the anti-derivative for $\dfrac{dy}{dx}=9x^2-4x+5$
Thus, we have: $y=3x^3-2x^2+5x+C$
Apply the initial conditions $y(-1)=0$ in the above equation to solve for $C$.
we get: $-3-2-5+C=0 \implies C=10$
Hence, $y=3x^3-2x^2+5x+10$
