Answer
True
Work Step by Step
We have: $\dfrac{d}{dx}[(\dfrac{x+3}{x-2})^3+C]$
$\dfrac{d}{dx}[(\dfrac{x+3}{x-2})^3+C] =(3) (\dfrac{x+3}{x-2})^2 (\dfrac{5}{(x-2)^2})=-15\dfrac{(x+3)^2}{(x-2)^4}$
Hence, the statement is true.
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