University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 273: 91



Work Step by Step

We need to find the anti-derivative for $\dfrac{dy}{dx}=2x-7$ Thus, we have $y=x^2-7x+C$ Apply the initial conditions in the above equation to solve for $C$. we get $2^2-7(2)x+C=0 \implies C=10$ Hence, $y=x^2-7x+10$
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