University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 273: 92



Work Step by Step

We need to find the anti-derivative for $\dfrac{dy}{dx}=10-x$ Thus, we have $y=10x-\dfrac{x^2}{2}+C$ Apply the initial conditions in the above equation to solve for $C$. we get: $0+C=-1 \implies C=-1$ Hence,$y=10x-\dfrac{x^2}{2}-1$
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