Answer
$y=2x$
Work Step by Step
We need to find the anti-derivative for $\dfrac{d^2y}{dx^2}=0$
We have: $\dfrac{dy}{dx}=c$; $y=cx+c'$
Apply the initial conditions $y'(0)=2 ; y(0)=0$
Thus, $c=2$ and $0+c'=0 \implies c'=0$
Hence, $y=2x$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 273: 106
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