University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.5 - Derivatives of Trigonometric Functions - Exercises - Page 151: 34

Answer

a)$y' = -2cosx$ $y'' = 2sinx$ $y''' = 2cosx$ $y'''' = -2sinx$ b) $y' = -9sinx$ $y'' = -9cosx$ $y''' = 9sinx$ $y'''' = 9cosx$

Work Step by Step

a) $y = -2sinx$ $y' = -2cosx$ $y'' = 2sinx$ $y''' = 2cosx$ $y'''' = -2sinx$ b) $y = 9cosx$ $y' = -9sinx$ $y'' = -9cosx$ $y''' = 9sinx$ $y'''' = 9cosx$
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