University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.5 - Derivatives of Trigonometric Functions - Exercises - Page 151: 25

Answer

$r' = sec^{2}\theta - cosec^{2}\theta$

Work Step by Step

$r = sec\theta\ cosec\theta$ $r' = sec\theta\ tan\theta\ cosec\theta - sec\theta\ cosec\theta\ cot\theta$ $r' = sec^{2}\theta - cosec^{2}\theta$
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