University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.5 - Derivatives of Trigonometric Functions - Exercises - Page 151: 20

Answer

$s' = 2t - secx\ tanx + 5e^{t}$

Work Step by Step

$s = t^{2}-sect+5e^{t}$ $s' = 2t - secx\ tanx + 5e^{t}$
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