Answer
$y' = x^{2} + x - e^{-x}$
$y'' = 2x +1 +e^{-x}$
Work Step by Step
$y = \frac{x^{3}}{3} + \frac{x^{2}}{2}+ e^{-x}$
$y' = \frac{3x^{3-1}}{3} + \frac{2x^{2-1}}{2} - e^{-x}$
$y' = x^{2} + x - e^{-x}$
$y'' = 2x +1 +e^{-x}$
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