University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 135: 13

Answer

$y' = -5x^{4}+12x^{2}-2x -3$

Work Step by Step

Using product rule: $y = (3-x^{2})(x^{3} - x +1)$ $y' = (3-x^{2})(3x^{2} - 1+0) + (x^{3} - x +1)(-2x)$ $y' = -5x^{4} + 12x^{2}-2x-3$ Using sum of simpler terms: $y = -x^{5}+4x^{3} - x^{2} - 3x +3$ $y' = -5x^{4}+12x^{2}-2x -3$
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