Answer
$w' = 21z^{6}-21z^{2}+42z^{1}$
$w'' = 126z^{5}- 42z+42$
Work Step by Step
$w = 3z^{7}-7z^{3}+21z^{2}$
$w' = 21z^{7-1}-21z^{3-1}+42z^{2-1}$
$w' = 21z^{6}-21z^{2}+42z^{1}$
$w'' = 126z^{6-1}- 42z^{1}+42$
$w'' = 126z^{5}- 42z+42$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 135: 4
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