University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.3 - Differentiation Rules - Exercises: 4

Answer

$w' = 21z^{6}-21z^{2}+42z^{1}$ $w'' = 126z^{5}- 42z+42$

Work Step by Step

$w = 3z^{7}-7z^{3}+21z^{2}$ $w' = 21z^{7-1}-21z^{3-1}+42z^{2-1}$ $w' = 21z^{6}-21z^{2}+42z^{1}$ $w'' = 126z^{6-1}- 42z^{1}+42$ $w'' = 126z^{5}- 42z+42$
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