Answer
$y' = 30x^{2} +14x -12$
Work Step by Step
Using product rule:
$y = (2x+3)(5x^{2} -4x)$
$y' = (2x+3)(10x-4) + (5x^{2} -4x)(2)$
$y' = 30x^{2} +14x -12$
Using sum of simpler terms:
$y = 10x^{3} + 7x^{2} -12x$
$y' = 30x^{2} +14x -12$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 135: 14
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