Answer
$y' = \frac{-19}{(3x-2)^{2}}$
Work Step by Step
$y = \frac{2x+5}{3x-2}$
Using quotient rule:
$y' = \frac{(3x-2)(2) - (2x+5)(3)}{(3x-2)^{2}}$
$y' = \frac{-19}{(3x-2)^{2}}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 135: 17
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