University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 14 - Section 14.4 - Double Integrals in Polar Form - Exercises - Page 778: 17

Answer

$[1-\ln (2)] \pi $

Work Step by Step

Our aim is to integrate the integral as follows: $\int ^0_{-1} \int ^0_{-\sqrt{1-x^2}}\dfrac{2}{1+\sqrt{x^2+y^2}} \space dy \space dx $ or, $=\int^{3\pi/2}_{\pi} \int^1_0\dfrac{2r}{1+r} \space dr \space d\theta $ or, $=2\int^{3\pi/2}_{\pi} \int^{1}_0(1-\dfrac{1}{1+r}) \space dr \space d\theta $ or, $=2\int ^{3\pi/2}_\pi (1-\ln (2)) \space d\theta $ or, $=[1-\ln (2)] \pi $
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