Answer
Saddle point at $(n \pi,0)$
Work Step by Step
Since, we have $f_x(x,y)=y \cos x=0, f_y(x,y)=\sin x=0$
After solving the above two equations, we get
The critical point is: $(n \pi,0)$
As per the second derivative test, for $(n \pi,0)$ we have
$D=f_{xx}f_{yy}-f^2_{xy}=-1$ and $D=-1 \lt 0$
Thus, we have: Saddle point at $(n \pi,0)$