Answer
$f_x=2y (xy-1)$ and $f_y=2x(xy-1)$
Work Step by Step
Our aim is to take the first partial derivative of the given function $f(x,y)$ with respect to $x$, by keeping $y$ as a constant.
$f_x=2(xy-1)\times (y)$
Take the first partial derivative of the given function $f(x,y)$ with respect to $y$, by keeping $x$ as a constant.
$f_y=2(xy-1)\times (x)$
Our results are: $f_x=2y (xy-1)$ and $f_y=2x(xy-1)$
