Answer
∂f/∂x = 4x
∂f/∂y = -3
Work Step by Step
$f(x,y) = 2x^2 -3y -4$
1. Calculate ∂f/∂x.
$\frac{∂}{∂x}(2x^2) = 2*(2x) = 4x$
$\frac{∂}{∂x}(-3y) = 0$
$\frac{∂}{∂x}(-4) = 0$
Summing up these values:
$∂/∂x (2x^2 -3y -4) = 4x$
2. Calculate ∂f/∂y
$∂/∂y (2x^2) = 0$
$∂/∂y (-3y) = -3$
$∂/∂y (-4) = 0$
Summing up these values:
$∂/∂y (2x^2 -3y -4) = -3$
