University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.3 - Partial Derivatives - Exercises - Page 702: 32

Answer

$f_x=-yz \space e^{-xyz}$; $f_y=-xz \space e^{-xyz}$; $f_z=-xy \space e^{-xyz}$

Work Step by Step

Our aim is to take the first partial derivatives of the given function $f(x,y)$ with respect to $x$ , by keeping $y$ and $z$ as a constant, and vice versa: $f_x=-yz \space e^{-xyz}$; $f_y=-xz \space e^{-xyz}$; $f_z=-xy \space e^{-xyz}$
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