Answer
$∂f/∂x = 2x - y$
$∂f/∂y = 2y - x$
Work Step by Step
$f(x,y) = x^2 - xy + y^2$
1. Calculate $∂f/∂x$:
$∂/∂x(x^2 - xy + y^2):$
$∂/∂x(x^2) = 2x$
$∂/∂x(-xy) = -y$
$∂/∂x(y^2) = 0$
Summing all these values: $∂f/∂x = 2x - y$
2. Calculte $∂f/∂y$:
$∂/∂y(x^2 - xy + y^2)$ :
$∂/∂y(x^2) = 0$
$∂/∂y(-xy) = -x$
$∂/∂y(y^2) = 2y$
Summing all these values: $∂f/∂y = 2y - x$