Answer
$∂f/∂x = 2x(y+2)$
$∂f/∂y = x^2-1$
Work Step by Step
$f(x,y) = (x^2-1)(y+2)$
1. Find $∂f/∂x$:
Using the chain rule:
$∂f/∂x = (x^2-1)'(y+2) + (x^2-1)(y+2)'$
**$∂/∂x(x^2-1) = 2x$
**$∂/∂x(y+2) = 0$
$∂f/∂x= 2x * (y +2) + (x^2-1)(0)$
$∂f/∂x = 2x(y+2)$
2. Find $∂f/∂y$:
Using the chain rule:
$∂f/∂y = (x^2-1)'(y+2) + (x^2-1)(y+2)'$
** $∂/∂y(x^2-1) = 0$
** $∂f/∂y(y+2) = 1$
$∂f/∂y = 0(y+2) + (x^2-1)*(1)$
$∂f/∂y = x^2-1$