Chapter 11 - Section 11.5 - Lines and Planes in Space - Exercises - Page 631: 55

$(1,1,0)$

The parametric equations are: $x=1+2t; y=1+5t; z=3t$ We have the equation of a plane: $x+y+z=2$ Now, we plug in all of the parametric equations into the above equation of a plane: $t=0$ Thus, our parametric equations become: $x=1+2(0)=1; y=1+5(0)=1; z=3(0)=0$ Hence, the line will meet at the point: $(1,1,0)$