Answer
$\dfrac{\sqrt {14}}{\sqrt {3}}=\dfrac{\sqrt {42}}{3}$
Work Step by Step
The formula to calculate the distance for two vectors is given by:
$d=\dfrac{|u \times v|}{|v|}$
Thus, we have $u \times v=\lt -2,6,-4\gt $
and $|u \times v|=\sqrt{(-2)^2+(6)^2+(-4)^2}=2 \sqrt {14}$
Now, $d=\dfrac{|u \times v|}{|v|}=\dfrac{2 \sqrt {14}}{2 \sqrt {3}}=\dfrac{\sqrt {42}}{3}$
