Chapter 11 - Section 11.5 - Lines and Planes in Space - Exercises - Page 631: 37

$\dfrac{9 \sqrt {42}}{7}$

The formula to calculate the distance for two vectors is given by: $d=\dfrac{|u \times v|}{|v|}$ Thus, we have $u \times v=\lt 30,6,6\gt $ and $|u \times v|=\sqrt{(30)^2+(6)^2+(6)^2}=18 \sqrt {3}$ Now, $d=\dfrac{|u \times v|}{|v|}=\dfrac{18 \sqrt {3}}{ \sqrt {14}}=\dfrac{9 \sqrt {42}}{7}$